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tippero
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Make another JSON reply log on a single line

This commit is contained in:
moneromooo 2015-01-25 18:31:02 +00:00
parent c096f9d6e3
commit 099981b832
1 changed files with 2 additions and 3 deletions
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5
tipbot/utils.py
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@ -160,13 +160,12 @@ def SendHTMLCommand(host,port,method):
http.close()
raise
response = http.getresponse()
log_log('SendHTMLCommand: Received reply status: %s' % response.status)
if response.status != 200:
log_error('SendHTMLCommand: Error, not 200: %s' % str(response.status))
log_error('SendHTMLCommand: Error, received reply status %s' % str(response.status))
http.close()
raise RuntimeError("Error "+response.status)
s = response.read()
log_log('SendHTMLCommand: Received reply: %s' % s)
log_log('SendHTMLCommand: Received reply status %s: %s' % (response.status,s.replace('\r\n',' ').replace('\n',' ')))
try:
j = json.loads(s)
except Exception,e: