[vimeo] Fix and use '_verify_video_password' (#5001)

It only supports verifying the password over https now.

Use it instead of manually setting the 'password' cookie because it allows to check if the password is correct.
This commit is contained in:
Jaime Marquínez Ferrándiz 2015-03-06 19:08:27 +01:00
parent 3c6f245083
commit 9c85b5376d
1 changed files with 6 additions and 14 deletions

View File

@ -4,7 +4,6 @@ from __future__ import unicode_literals
import json
import re
import itertools
import hashlib
from .common import InfoExtractor
from ..compat import (
@ -178,17 +177,15 @@ class VimeoIE(VimeoBaseInfoExtractor):
password = self._downloader.params.get('videopassword', None)
if password is None:
raise ExtractorError('This video is protected by a password, use the --video-password option', expected=True)
token = self._search_regex(r'xsrft: \'(.*?)\'', webpage, 'login token')
data = compat_urllib_parse.urlencode({
token = self._search_regex(r'xsrft = \'(.*?)\'', webpage, 'login token')
data = urlencode_postdata({
'password': password,
'token': token,
})
# I didn't manage to use the password with https
if url.startswith('https'):
pass_url = url.replace('https', 'http')
else:
pass_url = url
password_request = compat_urllib_request.Request(pass_url + '/password', data)
if url.startswith('http://'):
# vimeo only supports https now, but the user can give an http url
url = url.replace('http://', 'https://')
password_request = compat_urllib_request.Request(url + '/password', data)
password_request.add_header('Content-Type', 'application/x-www-form-urlencoded')
password_request.add_header('Cookie', 'xsrft=%s' % token)
return self._download_webpage(
@ -227,11 +224,6 @@ class VimeoIE(VimeoBaseInfoExtractor):
if mobj.group('pro') or mobj.group('player'):
url = 'http://player.vimeo.com/video/' + video_id
password = self._downloader.params.get('videopassword', None)
if password:
headers['Cookie'] = '%s_password=%s' % (
video_id, hashlib.md5(password.encode('utf-8')).hexdigest())
# Retrieve video webpage to extract further information
request = compat_urllib_request.Request(url, None, headers)
try: