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tests/cache_test: use the blob key's actual first byte 

There is no need to hardcode it, we can just use blob_key[0].
This is needed because the next patches are going to change how cache
keys are computed.

Signed-off-by: Grazvydas Ignotas <notasas@gmail.com>
Reviewed-by: Timothy Arceri <tarceri@itsqueeze.com>
This commit is contained in:
Grazvydas Ignotas 2017-03-16 01:09:28 +02:00 committed by Timothy Arceri
parent 529a767041
commit af73acca2b
1 changed files with 2 additions and 6 deletions
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8
src/compiler/glsl/tests/cache_test.c
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@ -255,12 +255,8 @@ static void
test_put_and_get(void)
{
struct disk_cache *cache;
/* If the text of this blob is changed, then blob_key_byte_zero
* also needs to be updated.
*/
char blob[] = "This is a blob of thirty-seven bytes";
uint8_t blob_key[20];
uint8_t blob_key_byte_zero = 0xca;
char string[] = "While this string has thirty-four";
uint8_t string_key[20];
char *result;
@ -333,7 +329,7 @@ test_put_and_get(void)
* directory as the original blob first written to the cache.
*/
disk_cache_compute_key(cache, one_KB, 1024, one_KB_key);
one_KB_key[0] = blob_key_byte_zero;
one_KB_key[0] = blob_key[0];
disk_cache_put(cache, one_KB_key, one_KB, 1024);
@ -403,7 +399,7 @@ test_put_and_get(void)
one_MB = calloc(1024, 1024);
disk_cache_compute_key(cache, one_MB, 1024 * 1024, one_MB_key);
one_MB_key[0] = blob_key_byte_zero;;
one_MB_key[0] = blob_key[0];
disk_cache_put(cache, one_MB_key, one_MB, 1024 * 1024);