pan/midgard: Fix quadword_count handling
Spilling can mess with this considerably. Signed-off-by: Alyssa Rosenzweig <alyssa.rosenzweig@collabora.com>
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@ -2359,10 +2359,10 @@ midgard_get_first_tag_from_block(compiler_context *ctx, unsigned block_idx)
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unsigned first_tag = 0;
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mir_foreach_block_from(ctx, initial_block, v) {
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midgard_bundle *initial_bundle =
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util_dynarray_element(&v->bundles, midgard_bundle, 0);
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if (v->quadword_count) {
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midgard_bundle *initial_bundle =
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util_dynarray_element(&v->bundles, midgard_bundle, 0);
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if (initial_bundle) {
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first_tag = initial_bundle->tag;
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break;
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}
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@ -1072,7 +1072,9 @@ schedule_block(compiler_context *ctx, midgard_block *block)
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/* Blend constant was backwards as well. blend_offset if set is
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* strictly positive, as an offset of zero would imply constants before
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* any instructions which is invalid in Midgard */
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* any instructions which is invalid in Midgard. TODO: blend constants
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* are broken if you spill since then quadword_count becomes invalid
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* XXX */
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if (blend_offset)
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ctx->blend_constant_offset = ((ctx->quadword_count + block->quadword_count) - blend_offset - 1) * 0x10;
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@ -547,6 +547,7 @@ mir_insert_instruction_before_scheduled(
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memcpy(bundles + before, &new, sizeof(new));
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list_addtail(&new.instructions[0]->link, &before_bundle->instructions[0]->link);
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block->quadword_count += quadword_size(new.tag);
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}
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void
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@ -571,6 +572,7 @@ mir_insert_instruction_after_scheduled(
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midgard_bundle new = mir_bundle_for_op(ctx, ins);
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memcpy(bundles + after + 1, &new, sizeof(new));
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list_add(&new.instructions[0]->link, &after_bundle->instructions[after_bundle->instruction_count - 1]->link);
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block->quadword_count += quadword_size(new.tag);
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}
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/* Flip the first-two arguments of a (binary) op. Currently ALU
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