intel/common: Support bigger right-shifts with mi_builder
Because why not?
This commit is contained in:
parent
0d6dea0ac8
commit
316a98dec9
|
@ -689,6 +689,18 @@ gen_mi_ushr32_imm(struct gen_mi_builder *b,
|
|||
/* We right-shift by left-shifting by 32 - shift and taking the top 32 bits
|
||||
* of the result. This assumes the top 32 bits are zero.
|
||||
*/
|
||||
if (shift > 64)
|
||||
return gen_mi_imm(0);
|
||||
|
||||
if (shift > 32) {
|
||||
struct gen_mi_value tmp = gen_mi_new_gpr(b);
|
||||
_gen_mi_copy_no_unref(b, gen_mi_value_half(tmp, false),
|
||||
gen_mi_value_half(src, true));
|
||||
_gen_mi_copy_no_unref(b, gen_mi_value_half(tmp, true), gen_mi_imm(0));
|
||||
gen_mi_value_unref(b, src);
|
||||
src = tmp;
|
||||
shift -= 32;
|
||||
}
|
||||
assert(shift <= 32);
|
||||
struct gen_mi_value tmp = gen_mi_ishl_imm(b, src, 32 - shift);
|
||||
struct gen_mi_value dst = gen_mi_new_gpr(b);
|
||||
|
|
|
@ -625,15 +625,20 @@ TEST_F(gen_mi_builder_test, ushr32_imm)
|
|||
const uint64_t value = 0x0123456789abcdef;
|
||||
memcpy(input, &value, sizeof(value));
|
||||
|
||||
const unsigned max_shift = 31;
|
||||
const unsigned max_shift = 64;
|
||||
|
||||
for (unsigned i = 0; i <= max_shift; i++)
|
||||
gen_mi_store(&b, out_mem64(i * 8), gen_mi_ushr32_imm(&b, in_mem64(0), i));
|
||||
|
||||
submit_batch();
|
||||
|
||||
for (unsigned i = 0; i <= max_shift; i++)
|
||||
EXPECT_EQ(*(uint64_t *)(output + i * 8), (value >> i) & UINT32_MAX);
|
||||
for (unsigned i = 0; i <= max_shift; i++) {
|
||||
if (i >= 64) {
|
||||
EXPECT_EQ(*(uint64_t *)(output + i * 8), 0);
|
||||
} else {
|
||||
EXPECT_EQ(*(uint64_t *)(output + i * 8), (value >> i) & UINT32_MAX);
|
||||
}
|
||||
}
|
||||
}
|
||||
|
||||
TEST_F(gen_mi_builder_test, udiv32_imm)
|
||||
|
|
Loading…
Reference in New Issue