glsl: Fix copying function's out to temp if dereferenced by array
Function's out variable could be an array dereferenced by an array:
func(v[w[i]]);
or something more complicated.
Copy index in any case.
Fixes: 76c27e47b9
("glsl: Copy function out to temp if we don't directly ref a variable")
Signed-off-by: Danylo Piliaiev <danylo.piliaiev@globallogic.com>
Reviewed-by: Timothy Arceri <tarceri@itsqueeze.com>
Reviewed-by: Matt Turner <mattst88@gmail.com>
Reviewed-by: Kenneth Graunke <kenneth@whitecape.org>
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@ -363,13 +363,12 @@ copy_index_derefs_to_temps(ir_instruction *ir, void *data)
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ir = a->array->as_dereference();
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ir_rvalue *idx = a->array_index;
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if (idx->as_dereference_variable()) {
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ir_variable *var = idx->variable_referenced();
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/* If the index is read only it cannot change so there is no need
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* to copy it.
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*/
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if (var->data.read_only || var->data.memory_read_only)
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if (!var || var->data.read_only || var->data.memory_read_only)
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return;
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ir_variable *tmp = new(d->mem_ctx) ir_variable(idx->type, "idx_tmp",
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@ -388,7 +387,6 @@ copy_index_derefs_to_temps(ir_instruction *ir, void *data)
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new(d->mem_ctx) ir_dereference_variable(tmp);
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a->array_index = deref_tmp_2;
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}
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}
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}
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static void
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